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27a^2-108=0
a = 27; b = 0; c = -108;
Δ = b2-4ac
Δ = 02-4·27·(-108)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-108}{2*27}=\frac{-108}{54} =-2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+108}{2*27}=\frac{108}{54} =2 $
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